Again about the zigzags mechanical experiment :)

Science and Technology
1

To mrmhead and to the other colleagues, who are interested in the topic

Shall we re-start again our discussion, related to the zigzags?:slight_smile:
Please answer the two simple questions below, if possible.
Looking forward to your two answers.

Consider carefully and thoroughly (and many times, if necessary!) the link Perpetual motion and reactionless drive - YouTube

Ma = 1 kg
Mb = 4 kg. (The value of Mb can be either increased or decreased as many times as you want.)
V1 = 1m/s = const
Ffr. = force of friction inside the zigzag channels = 0.0000001 N. (The latter can be further decreased as many times as you want.)
N = number of zigzags = 10. (The value of N can be either increased or decreased as many times as you want.)
Shapes of the zigzags = sinusoids. (The latter can replaced by any other curve patterns.)

QUESTION 1: V2 = ? (How many meters per second is V2 equal to?)
QUESTION 2: V3 = ? (How many meters per second is V3 equal to?)

Please answer the above two simple questions, if possible.
Looking forward to your two answers.

2

Please answer the two simple questions below, if possible.
QUESTION 1: V2 = ? (How many meters per second is V2 equal to?)
QUESTION 2: V3 = ? (How many meters per second is V3 equal to?)
Please answer the above two simple questions, if possible.
Looking forward to your two answers.

3

Asking my two simple questions for the 2nd time.
QUESTION 1: V2 = ? (How many meters per second is V2 equal to?)
QUESTION 2: V3 = ? (How many meters per second is V3 equal to?)
Looking forward to your two answers for the 2nd time.

4

Let us push forward together the technology progress!

Asking my two simple questions again.

  1. Consider carefully and thoroughly (and many times!) the link Perpetual motion and reactionless drive - YouTube .
  1. Assume that:
    a) Ma = 1 kg;
    b) Mb = 4 kg; the value of Mb can be either increased or decreased as many times as you want;
    c) V1 = 1m/s = const;
    d) Ffr. = force of friction inside the zigzag channels = 0.0000001 N; the latter can be further decreased as many times as you want;
    e) N = number of zigzags = 10; the value of N can be either increased or decreased as many times as you want;
    f) Shapes of the zigzags = sinusoids; the latter can be replaced by any other curve patterns.
  1. It is evident that if V2 = 0.6 m/s and if V3 = 0.1 m/s, then (a) the law of conservation of linear momentum will be correct and (b) the law of conservation of mechanical energy will be incorrect.
  1. It is evident that if V2 = 0.8 m/s and if V3 = 0.3 m/s, then (a) the law of conservation of linear momentum will be incorrect and (b) the law of conservation of mechanical energy will be correct.
  1. Or may be both (a) the law of conservation of linear momentum and (b) the law of conservation of mechanical energy are actually incorrect simultaneously in this special particular zigzag case?

So let us ask again our two simple questions again.

QUESTION 1: V2 = ? (How many meters per second is V2 equal to?)
QUESTION 2: V3 = ? (How many meters per second is V3 equal to?)

Looking forward to your two answers.

Let us push forward together the technology progress!

5

Obviously, this topic is going nowhere. These questions have been responded to elsewhere. Repetition is discussed in the rules.

https://forum.centerforinquiry.org/faq#rule3

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