The common distance of the stars , by Aetzbar ………………………………………………………………1

Countlees stars moving infinite space.

The stars are combined according to the idea of a central star , and ather stars revolving

around it. Each star is a central star and ather star, at the same time.

Kepler discovered the univerce formula D^3 : T^2 = P ( P is number )

D – The distance of ather star from central star.

T – Time that ather star rotates around a central star.

Newton : Each star has its material quantity ( M – view Newton)

M determines P that appesrs in Kepler’s universe formula.

If M will increase 5 times,then either P increase 5 times.

How to get the P of earth ? with Kepler’s universe formula. D^3 : T^2 = P

The earth is a central star for the moon.

Moon is far from earth 384000 km, and time it orbited the earth 672 hours.

P = 384000^3 : 672^2 = 1.25*10^11
P of earth is determined by M of earth.
There are an infinite number of combination of D and T ,if selected D ,the formula tell us T. If you want to send a satellite to earth, a height of 88000 km ,time it will circle the earth,
predetermined. T = root of ( 88000^3 : 1.25*10^11) = 74 hours

Finding p of the Sun.

The Sun is a central star for the earth (with the moon moves around)

P is obtained by the distance ( Earth – Sun) and time of 1 year in hours.

P of Sun = 429

*10^14 P of the Sun determined by M of the Sun.*

The common distance of the stars , by Aetzbar ………………………………………………………………2

Galileo introduced an imaginary experiment , in which a ball falls to the entrance of a

Tunnel that reaches the other side of the earth. This ball will illustrate a pendulum

Movement , between the two openings of the tunnel.

The cycle time will be 1.4 hours. Marked ]T[

P of earth and ]T[ of earth ,determines by M of earth.

The common distance of the stars

As we move away from a star, lap time around it will grow. ( T increases) Therefore ,the

Equality T = ]T[ must appear each star, at some distance from the center of the star.

So that all the stars in the universe will be in harmony, need only a single distance which appears the equality T = ]T[

How do we find the common distance of the stars ?

Since M of star determines its P and ]T[ , must be a connection between P and ]T[

The connection is P]T[^2 = number

The common distance of the stars , by Aetzbar ………………………………………………………………2

Galileo introduced an imaginary experiment , in which a ball falls to the entrance of a

Tunnel that reaches the other side of the earth. This ball will illustrate a pendulum

Movement , between the two openings of the tunnel.

The cycle time will be 1.4 hours. Marked ]T[

P of earth and ]T[ of earth ,determines by M of earth.

The common distance of the stars

As we move away from a star, lap time around it will grow. ( T increases) Therefore ,the

Equality T = ]T[ must appear each star, at some distance from the center of the star.

So that all the stars in the universe will be in harmony, need only a single distance which appears the equality T = ]T[

How do we find the common distance of the stars ?

Since M of star determines its P and ]T[ , must be a connection between P and ]T[

The connection is P

This connection will reveal the common distance of the stars.

P of earth = 1.3*10^11 and ]T[ of earth = 1.4 hours

1.3 * 10^11)

*1.4^2 = 2.5 * 10^11 )*

( D^3 : T^2) * [T[^2 = 2.5 * 10^11

T = ]T[

D^3 = 2.510^11

( D^3 : T^2) * [T[^2 = 2.5 * 10^11

T = ]T[

D^3 = 2.5

D = 6300 kilometers

The common distance of the stars = 6300 km

Satellite close to the ground, makes a complete revolution in 1.4 hours.

]T[ of earth is 1.4 hours.

Earth space are within 6300 km from the center of the earth.